:has()用于查找奇数gird网格

2022-08-15135次阅读css模块css

:has()用于查找奇数gird网格

.items {
	display: grid;
	grid-template-columns: repeat(auto-fit, minmax(200px, 1fr));
	gap: 5vw;
}

@media (max-width: 800px) {
	.items {
    grid-template-columns: 1fr 1fr;
  }
	
	.items:has(.item:last-of-type:nth-of-type(odd)) .item:first-of-type {
		grid-column: 1 / -1;
	}
}
  • 我们有一个.items.
  • 如果容器是其类型的最后:has()一个子容器,.item
  • ……这.item恰好是一个奇数实例,
  • …然后选择该.item类型的第一个元素并为其设置样式!

利用 CSS Grid 的自动放置算法,我们甚至不必为网格显式声明固定数量的列和行——如果需要,CSS 会为我们创建它们!

html

<div class="controls">
  <p>This grid sports a pattern that alternates by row and forces the last grid item to span all the columns if there is an odd number of grid items.</p>
  <p>⚠️ Safari TP and Edge/Chrome Canary support at the moment.</p>
  <button onclick="addItem()">Add Item</button>
  <button onclick="removeItem()">Remove Item</button>
</div>

<div class="grid">
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
  <div></div>
</div>

css

.grid {
  display: grid;
  grid-auto-rows: 100px;
  grid-auto-columns: 1fr;
  grid-gap: 5px;
}
.grid :nth-child(4n + 1) {
  grid-column: span 2;
}
.grid :nth-child(4n + 4) {
  grid-column: 2 / span 2;
}

.grid:has(div:last-of-type:nth-of-type(odd)) div:last-of-type {
  grid-column: 1 / 4;
}

/**/
.grid {
  max-width: 600px;
  margin: auto;
  counter-reset: num;
}
.grid * {
  border: 2px solid;
  font-size: 30px;
  box-sizing: border-box;
  font-family: sans-serif;
  display: grid;
  place-content: center;
}
.grid *:before {
  content: counter(num);
  counter-increment: num;
}

/**/
.controls {
  background: #fafafa;
  font-family: Merriweather, serif;
  line-height: 1.5;
  margin: 1.35rem auto;
  max-width: 55ch;
  padding: 1.35rem;
}

摘自:https://css-tricks.com/implicit-grids-repeatable-layout-patterns-and-danglers/

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